07 Dec




















draw indefinitely a line parallel to the IL ; then the points a', b', c in this line, where the projectors from a, b, c in the plan cut it, will be the elevations of the three corners of the upper face of the frustum, seen when looking at it in the direction of the arrow x. Join a A', b' B, c'C' by straight lines, as shown, and the required elevation is obtained. Proceeding from the simple to the more difficult, our next problem is Problem 39. Given the plan of the frustum of a square pyramid resting on the HP, and surmounted by a cube, its sides being inclined to the VP ; required its elevation. Let Fig. 128 be the plan of the combined solid, in the position given in the problem, and let the height of the frustum be equal to the length of a side of the cube. Then, having found the elevation of the frustum, as in the last problem, find by projectors from points 1, 2, 3 in the plan the elevation of the three corners of the cube, seen when looking in the direction of the arrow. On the projector from point 1 in the plan set off from the upper face of the frustum, or the line a' If c, the height of the cube, and through the point 1' draw the line 1' 2' 3', and the required elevation is obtained. The elevation of any of the regular plane solids from their plan is found in the same way. For example MECHANICAL AND ENGINEERING DRAWING 74 FIRST PRINCIPLES OF Problem 40. Let Fig. 120, Slieet 8, be the plan of an hexagonal prism with its axis vertical and its base on the HP, and let its height be eqw.il to twice the diameter of the inscribed circle of its base ; required its elevation.

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